x^4-5x^2+40=

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Solution for x^4-5x^2+40= equation:


Simplifying
x4 + -5x2 + 40 = 0

Reorder the terms:
40 + -5x2 + x4 = 0

Solving
40 + -5x2 + x4 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -5x2 + -40 + x4 = 0 + -40

Reorder the terms:
40 + -40 + -5x2 + x4 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -5x2 + x4 = 0 + -40
-5x2 + x4 = 0 + -40

Combine like terms: 0 + -40 = -40
-5x2 + x4 = -40

The x term is -5x2.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5x2 + 6.25 + x4 = -40 + 6.25

Reorder the terms:
6.25 + -5x2 + x4 = -40 + 6.25

Combine like terms: -40 + 6.25 = -33.75
6.25 + -5x2 + x4 = -33.75

Factor a perfect square on the left side:
(x2 + -2.5)(x2 + -2.5) = -33.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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